Characteristics of rational functions
- Previous: ‹ Rational functions
- Up: Rational functions
- Next: Graphs of rational functions ›
Domain
- It must be determined before simplifying the function.
- The only restriction on the domain of a rational function is division by zero.
- Zeros (\(x\)-intercepts) of the denominator are disallowed in the domain of a rational function.
- The denominator of a rational function is a polynomial, which does not always have zeros. Therefore, not every rational function has restrictions on its domain.
- The domain of \(y=\frac{1}{x^2+1}\) is all real numbers, because \(x^2+1=0\) has no solutions.
- The domain of \(y=\frac{1}{x^2-1}\) is \(\{x\in\mathbb{R}\mid x\neq\pm 1\}\) because the solution of \(x^2-1=0\) is \(x=\pm1\).
Range
- There is no solid single rule for determining the range, and every case has to be considered individually.
- The function \(y=\frac{1}{x^2+1}\) has the range \(\{y\in\mathbb{R}\mid 0\lt y\le 1\}\).
- The range of \(y=\frac{1}{x^2}\) is \(\{y\in\mathbb{R}\mid y\gt 0\}\).
- The range of \(y=\frac{1}{x}\) is \(\{y\in\mathbb{R}\mid y\neq 0\}\).
\(\boldsymbol{x}\)-intercepts
- A rational function has \(x\)-intercepts wherever its numerator is zero,
- provided that the function is defined at that value of \(x\).
- To get the \(x\)-intercepts, we set the numerator of the simplified function equal to zero, and solve the equation.
- The numerator is a polynomial, which may or may not have zeros. Therefore, a rational function may or may not have zeros.
- The function \(y=\frac{x^2+1}{x-2}\) does not have zeros, because \(x^2+1=0\) has no zeors.
- The function \(y=\frac{x^2-1}{x-2}\) has zeros at \(x=\pm1\), because these are the zeros of \(x^2-1=0\).
\(\boldsymbol{y}\)-intercept
- A function has a \(y\)-intercept wherever \(x=0\).
- Therefore, a rational function has a \(y\)-intercept if and only if it is defined at \(x=0\).
- The function \(y=\frac{1}{x}\) does not have \(y\)-intercept because it is undefined at \(x=0\).
- The function \(y=\frac{1}{x-1}\) has a \(y\)-intercept at \((0,-1)\).
Vertical asymptotes
A rational function has vertical asymptotes wherever the simplified denominator is zero. Because the denominator is a polynomial, a rational function may or may not have vertical asymptotes.
A function never crosses its vertical asymptote.
Horizontal or oblique asymptote
These depend on the degrees of both the numerator and denominator. Let \(\operatorname{deg}(P)\) be the degree of the numerator and \(\operatorname{deg}(Q)\) be that of the denominator.
- If \(\operatorname{deg}(P)\lt\operatorname{deg}(Q)\), the function has a horizontal asymptote at \(y=0\)
- If \(\operatorname{deg}(P)=\operatorname{deg}(Q)\), the function has a horizontal asymptote at \(y=\dfrac{\text{Leading coefficient of numerator}}{\text{Leading coefficient of denominator}}\)
- If \(\operatorname{deg}(P)=\operatorname{deg}(Q)+1\), the function has an oblique asymptote at \(y=\text{quotient of }\dfrac{P(x)}{Q(x)}\)
- If \(\operatorname{deg}(P)\gt\operatorname{deg}(Q)+1\), the function has neither a horizontal nor an oblique asymptote
A rational function may cross its horizontal or oblique asymptote, but beyond a certain value of \(x\) (depending on the function) it will just keep approaching without touching it.
End behaviour
If a rational function has a horizontal asymptote, then \(y\) approaches the asymptote as \(x\) approaches \(\pm\infty\). To check whether it approaches from above or from below, evaluate the function for a relatively high value of \(x\) (e.g., \(x=100\) or \(x=1000\)) and compare that to the location of the asymptote.
If a rational function has an oblique asymptote or neither horizontal nor oblique asymptotes, then \(y\) approaches \(\pm\infty\) as \(x\) approaches \(\pm\infty\). To check which infinity it approaches, evaluate the function at a relatively high value of \(x\).
Symmetry
Depending on its exact definition, a rational function may be even, odd or neither. We can check this algebraically as follows.
- A function is odd if and only if \(f(-x)=-f(x)\).
- A function is even if and only if \(f(-x)=f(x)\).
- Otherwise, the function is neither odd nor neve.
Behaviour of a rational function
- Factor the numerator and the denominator. DO NOT simplify yet.
- Factors in the denominator give us restrictions on the domain. Denominator cannot be zero.
- Simplify
- Factors that disappear from the denominator give us holes. To know the \(y\)-coordinate of the hole, substitute with the \(x\)-value into the simplified function.
- Factors that remain in the denominator give us vertical asymptotes.
- Factors that remain in the numerator give us \(\boldsymbol x\)-intercepts provided that the function is defined there (i.e., does not have holes or vertical asymptotes).
- To get the \(y\)-intercept, substitute with \(x=0\) (if it the function is defined there).
- To determine whether the function has horizontal or oblique asymptotes, compare the degrees of the numerator and denominator as described above.